No, not correct.
1) his actual velocity sqrt(1.5^2+.05^2)
2)time=500/1.5
3) distancedownstream=.05*time in b.
a) the actual velocity of the swimmer
b) how long it will tale to reach the far shore
c) how far donstream the swimmer will hit the opposite shore.
So far I'm using pythagorean theorem to find the hypotenuse; I'm doing the squre root of 500^2+.5^2 and that's givving me 500.00025, but I don't really think I'm doing this correctly; I'd really appreciate some help with this. :)
1) his actual velocity sqrt(1.5^2+.05^2)
2)time=500/1.5
3) distancedownstream=.05*time in b.
Could you mind explainig how you got the velocity, please?
a) To find the actual velocity of the swimmer, you can use the Pythagorean theorem. The horizontal component is 1.5 m/s, and the vertical component is 0.05 m/s. So, the actual velocity can be calculated as follows:
v_actual = sqrt((1.5^2) + (0.05^2)) = sqrt(2.2525) ≈ 1.50 m/s
Therefore, the actual velocity of the swimmer is approximately 1.50 m/s.
b) To find how long it will take to reach the far shore, you can divide the distance by the horizontal component of the velocity:
time = distance / velocity
distance = 500 m (width of the river)
velocity = 1.5 m/s (horizontal component of the velocity)
time = 500 m / 1.5 m/s ≈ 333.33 s
Therefore, it will take approximately 333.33 seconds, or about 5 minutes and 33 seconds, for the swimmer to reach the far shore.
c) To find how far downstream the swimmer will hit the opposite shore, you can multiply the vertical component of the velocity by the time taken:
distance_downstream = velocity_vertical * time
velocity_vertical = 0.05 m/s (vertical component of the velocity)
time = 333.33 s
distance_downstream = 0.05 m/s * 333.33 s ≈ 16.67 m
Therefore, the swimmer will hit the opposite shore approximately 16.67 meters downstream from the starting point.