Asked by eric
A swimmer swims perpendicular to the bank of a 20.0 m wide river at a velocity of
1.3 m/s. Suppose the river has a current of 2.7 m/s [W].
(a) How long does it take the swimmer to reach the other shore?
(b) How far downstream does the swimmer land from his intended location?
1.3 m/s. Suppose the river has a current of 2.7 m/s [W].
(a) How long does it take the swimmer to reach the other shore?
(b) How far downstream does the swimmer land from his intended location?
Answers
Answered by
Henry
X = -2.7 m/s.
Y = 1.3 m/s.
Q2.
a. Tan A = Y/X = 1.3/-2.7 = -0.48148.
A = -25.7 m/s = 25.7o N. of W. = 64.3o
W. of N. = Direction.
Vr = Sqrt(X^2 + Y^2) = Sqrt(2.7^2+1.3^2)= 3.0 m/s = Resultant velocity.
Dr = Sqrt(20^2 + 41.5^2) = 46.1 m. = Resultant distance.
Dr = Vr*T = 46.1 m.
T = 46.1/Vr = 46.1/3 = 15.4 s.
b. d = 20*Tan64.3 = 41.5 m. Downstream.
Y = 1.3 m/s.
Q2.
a. Tan A = Y/X = 1.3/-2.7 = -0.48148.
A = -25.7 m/s = 25.7o N. of W. = 64.3o
W. of N. = Direction.
Vr = Sqrt(X^2 + Y^2) = Sqrt(2.7^2+1.3^2)= 3.0 m/s = Resultant velocity.
Dr = Sqrt(20^2 + 41.5^2) = 46.1 m. = Resultant distance.
Dr = Vr*T = 46.1 m.
T = 46.1/Vr = 46.1/3 = 15.4 s.
b. d = 20*Tan64.3 = 41.5 m. Downstream.
Answered by
-
how did you fins 41.5??
Answered by
Azula Xero
(2.7)(41.50)
=41.5
=41.5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.