Asked by Anonymous
If I have 2.5L of propane at STP, how many grams of water can be produced by this combustion?
Answers
Answered by
Anonymous
I know STP is 22.4 L, but I need more help
Answered by
oobleck
so, you have 2.5/22.4 = 0.1116 moles of propane
Now look at the reaction equation for the combustion to see how many moles of water that will produce
then convert that to grams
Now look at the reaction equation for the combustion to see how many moles of water that will produce
then convert that to grams
Answered by
Anonymous
Ok so this is the equation:
C3H8 + 5O2 = 3CO2 + 4H2O
What do I have to do next?
C3H8 + 5O2 = 3CO2 + 4H2O
What do I have to do next?
Answered by
DrBob222
So you have 0.1116 mols propane. According to your balanced equation, 1 mol C3H8 will produce 4 mols H2O. That means 0.1116 mols C3H8 will produce .......mols H2O.
Answered by
Anonymous
Ahh, I get it now thank you
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