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Asked by Mary

If a Sequoia tree is 285 ft. High and has a diameter of 36.45 ft and an estimated wait of 2150 tons, what is the circumference to the nearest tenth?
6 years ago

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Answered by oobleck
circumference = pi * diameter
6 years ago
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If a Sequoia tree is 285 ft. High and has a diameter of 36.45 ft and an estimated wait of 2150 tons, what is the circumference to the nearest tenth?

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