Asked by Kd

The lengths of three wires were 30m, 36 m and 84m. Pieces of wire of equal length were cut from the three wires. Calculate the least number of pieces obtained.
Answered by Reiny
LCF of 30,36,84 is 6
so if we make 5 cuts of 6 m from the smallest
6 cuts from the 2nd
and 14 pieces from the third for a total of 25 pieces

Answered by Christine
LCM of 30,36,84=6
30/6=5
36/6=6
84/6=14
Therefore the total pieces are
5+6+14=25 pieces
Answered by Jeruto
God of 30,36 and 84 is 6.
30/6 is 5
36/6 is 6
84/6 is 14
Number of pieces obtained is 5+6+14=25
Answered by Okari
30- 2×3×5
36- 2²×3²
84- 2²×3×7
GCD - 2×3
Pieces obtained. (30÷6)+ (36÷6) + (84÷6)
5+6+14= 25 pieces.
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