Asked by Kd
The lengths of three wires were 30m, 36 m and 84m. Pieces of wire of equal length were cut from the three wires. Calculate the least number of pieces obtained.
Answers
Answered by
Reiny
LCF of 30,36,84 is 6
so if we make 5 cuts of 6 m from the smallest
6 cuts from the 2nd
and 14 pieces from the third for a total of 25 pieces
so if we make 5 cuts of 6 m from the smallest
6 cuts from the 2nd
and 14 pieces from the third for a total of 25 pieces
Answered by
Christine
LCM of 30,36,84=6
30/6=5
36/6=6
84/6=14
Therefore the total pieces are
5+6+14=25 pieces
30/6=5
36/6=6
84/6=14
Therefore the total pieces are
5+6+14=25 pieces
Answered by
Jeruto
God of 30,36 and 84 is 6.
30/6 is 5
36/6 is 6
84/6 is 14
Number of pieces obtained is 5+6+14=25
30/6 is 5
36/6 is 6
84/6 is 14
Number of pieces obtained is 5+6+14=25
Answered by
Okari
30- 2×3×5
36- 2²×3²
84- 2²×3×7
GCD - 2×3
Pieces obtained. (30÷6)+ (36÷6) + (84÷6)
5+6+14= 25 pieces.
36- 2²×3²
84- 2²×3×7
GCD - 2×3
Pieces obtained. (30÷6)+ (36÷6) + (84÷6)
5+6+14= 25 pieces.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.