Asked by Anonymous
                 Test the series for convergence or divergence. ∑from n=1 to ∞ ((n^3  -1)/(n^4+1))
            
            
        Answers
                    Answered by
            Anonymous
            
    I do the alternating seriestest. It shows that bn >0, (bn+1)<bn and the limit is 0. So, it is convergent  but the correct answer is divergent. Why?
 
    
                    Answered by
            oobleck
            
    why alternating series? All the terms are positive.
lim(n->∞) a_(n+1)/(a_n) = n^3/n^4 = 1/n
The harmonic series diverges
    
lim(n->∞) a_(n+1)/(a_n) = n^3/n^4 = 1/n
The harmonic series diverges
                    Answered by
            Anonymous
            
    Test the series for convergence or divergence.∑from n=1 to ∞ ((e^n) /n^2)
n = 1
    
n = 1
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