Asked by Daffodil_the_white_cat

By how much will a 2.05 kg object stretch a spring that is suspended vertically if the spring constant is 126 N/m?
Answered by henry2,
M*g = 2.05 * 9.8 = 20.1 N. = force of the object.
d = 1m/126N * 20.1N. =
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