If exactly 14.563g of KMnO4 were dissolved to yield 750mL of solution, what is the normality? I know the equivalent weight is 31.61g. This is how much I got.

Question

(14.563g/.750L)(1 mol KMnO4/158.03g)(5 e-/1 mol) = .615 This answer does not seem right however. If wrong, please explain

Answer 1

The conversion for potassium permanganate, KMnO4, from Normality to Molarity is 1N = 0.2M or 1M = 5N.

Molarity= 14.563/158*.750
now, normality = 5 * molarity above
You are correct.

Answer 2

Okay thank you Bob