Question

My homework question is to find the Laplace transform of the function f(t)=e^(10-2t)*step(t-5).
I am not sure how to handle the e^(10-2t) portion of the equation.
Thanks in advance.

Answer 1

e^(10-2t)= e^10 * e^-2 t
so
e^10 times transform of e^-2t u(t-5)

Answer 2

then to continue
given f(t) = e^at g(t)
then
F(s) = (1/a) G(s/a)

Answer 3

so....
e^10 (e^-2t) (1/s+5)?

Answer 4

or is it:

(e^10)(e^-2t)((e^-5t)/s) = (e^(10-7t))/s?