Question
A test solution is prepared by pipetting 2.0 mL of an original sample into a 250 mL volumetric flask and then diluting to the
mark. The concentration of iron in the test solution is determined (from a calibration curve) to be 1.66 μ g / mL or 1.66 ppm. What is the iron
concentration in the original sample
mark. The concentration of iron in the test solution is determined (from a calibration curve) to be 1.66 μ g / mL or 1.66 ppm. What is the iron
concentration in the original sample
Answers
1.66 μ g/mL*(250mL/2.0mL)=??????
2 Sig Figs
2 Sig Figs
207.5 M Fe
How much total iron (in mg) was in the original 2mL sample?
1.66 μ g/mL*(250mL/2.0mL)=?????? <==== Answer will be in μg/mL. Use the mw to convert it to mole and convert mL to L.
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