Asked by Sergejs
A solution was prepared using 1,00 liter of water, 59 g glucose, and 2,3 g NaCl. One liter of water weighs 1000 grams. The solution needs to be labeled in terms of % glucose and % sucrose.
Answers
Answered by
DrBob222
%by mass = (mass solute/mass solution)*100 = ?
mass solution = 1000gH2O + 59g glucose + 2.3g NaCl.
% glucose = (59/1061.3)*100 = ?
% NaCl = (2.3/1061.3)*100 = ?
% H2O = (1000/1061.2)*100 = ?
% sucrose = 0%
If your prof is picky about the number of significant figures be sure to round the final percent number to the correct number of s.f.
mass solution = 1000gH2O + 59g glucose + 2.3g NaCl.
% glucose = (59/1061.3)*100 = ?
% NaCl = (2.3/1061.3)*100 = ?
% H2O = (1000/1061.2)*100 = ?
% sucrose = 0%
If your prof is picky about the number of significant figures be sure to round the final percent number to the correct number of s.f.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.