Asked by ben

The pH of a solution prepared by mixing 45 mL of 0.183 M KOH and 65 mL of 0.145 M HCl is ?.
Answered by DrBob222
moles KOH = M x L = ??
moles HCl = M x L = ??
Which is in excess. by how much? That will be H^+ (if HCl is in excess) or OH^- (if KOH is in excess) and you determine pH from that final value.
Answered by BRett
.12
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