The pH of a solution prepared by mixing 45 mL of 0.183 M KOH and 65 mL of 0.145 M HCl is ?.

Answer 1

moles KOH = M x L = ??
moles HCl = M x L = ??
Which is in excess. by how much? That will be H^+ (if HCl is in excess) or OH^- (if KOH is in excess) and you determine pH from that final value.

Answer 2

.12