Asked by Rihit
                A distributes Rs.180 equally among a certain number of people. B distributes the same sum but gives to each  person Rs. 6 more than A does, and gives the same sum to 40 persons less than A does. How much does A gives to each person?
            
            
        Answers
                    Answered by
            Reiny
            
    number of people that A gives money to ---- n
each person's share = 180/n
number of people that B gives money to ---- n-40
each person's share in B episode = 180/(n-40)
the shares differ by 6 ----> 180/(n-40) - 180/n = 6
multiply each term by n(n-40)
180n - 180(n-40) = 6n(n-40)
7200 = 6n^2 - 240n
Carry on, let me know what answer you get.
    
each person's share = 180/n
number of people that B gives money to ---- n-40
each person's share in B episode = 180/(n-40)
the shares differ by 6 ----> 180/(n-40) - 180/n = 6
multiply each term by n(n-40)
180n - 180(n-40) = 6n(n-40)
7200 = 6n^2 - 240n
Carry on, let me know what answer you get.
                    Answered by
            Damon
            
    A:
each gets 180/n = x
so n = 180/x
B: (x+6)(n -40) = 180
(x+6)(180/x - 40) = 180
(x+6)(180 - 40 x ) = 180 x
180 x - 40 x^2 + 1080 - 240 x = 180 x
40 x^2 +240 x -1080 = 0
x^2 + 6x - 27 = 0
(x-9)(x+3) = 0
x = 9 (or - 3 )
    
each gets 180/n = x
so n = 180/x
B: (x+6)(n -40) = 180
(x+6)(180/x - 40) = 180
(x+6)(180 - 40 x ) = 180 x
180 x - 40 x^2 + 1080 - 240 x = 180 x
40 x^2 +240 x -1080 = 0
x^2 + 6x - 27 = 0
(x-9)(x+3) = 0
x = 9 (or - 3 )
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