Asked by BIZHATOCOTO
Solve for x in 16x^(-3) = 2x^(-6)?
Answers
Answered by
Reiny
6x^(-3) = 2x^(-6)
6/x^3 = 3/x^6
6x^6 = 3x^3
2x^6 - x^3 = 0
x^3(2x^3 - 1) = 0
take it from there
6/x^3 = 3/x^6
6x^6 = 3x^3
2x^6 - x^3 = 0
x^3(2x^3 - 1) = 0
take it from there
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