Question
a bullet of mass 120g is fired horizontally into a fixed wooden block with a speed of 20 m/s. If the bullet is brought to rest in the block in 0.1s by a constant resistance, calculate the
1) magnitude of the
2) Distance moved by the bullet in the wood.?
1) magnitude of the
2) Distance moved by the bullet in the wood.?
Answers
a = ∆v/∆t = -20/0.1 = -200 m/s^2
s = vt + 1/2 at^2 = 20*0.1 - 100*0.1^2 = ?
s = vt + 1/2 at^2 = 20*0.1 - 100*0.1^2 = ?
1. V = Vo + a*t = 0.
20 + a*0.1 = 0,
a = -200 m/s^2.
F = M*a = 0.120 * (-200) = -24 N. = opposing resistance.
20 + a*0.1 = 0,
a = -200 m/s^2.
F = M*a = 0.120 * (-200) = -24 N. = opposing resistance.
Thanks but can u break it down for me
Thanks but can you break it for me please
Tnx to but I need it in details please
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