Asked by Mark
A bullet of mass 4.7 g is fired horizontally into a 2.4 kg wooden block at rest on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.28. The bullet stops in the block, which slides straight ahead for 2.2 m (without rotation). (a) What is the speed of the block immediately after the bullet stops relative to it? (b) At what speed is the bullet fired?
Answers
Answered by
bobpursley
work done by block/bullet= totalmass*g*mu*distance
from that, compute the initial velocity of the block/bullet system (workdone=1/2 mv^2)
Now, knowing that velocity, use the conservation of momentum to find the initial velocity of the bullet
massbullet*vbullet= totalmass*Vyoufound
from that, compute the initial velocity of the block/bullet system (workdone=1/2 mv^2)
Now, knowing that velocity, use the conservation of momentum to find the initial velocity of the bullet
massbullet*vbullet= totalmass*Vyoufound
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