Question

If 3,p,q,24,are Consecutive Terms Of An Exponential Sequence,find The Values Of P And Q

Answer 1

24 = 3r^3
r^3 = 24/3 = 8
r = 2
so, ...

Answer 2

I do not know

Answer 3

Finish the solving

Answer 4

Let the common ratio be r then we have
3*r=p
P*r=q
Q*r=24
Divide the second equation by the first
P*r/3*r=q/p
P/3=q/p
P*2 =3q

Answer 5

From the third equation, we have:

q = 24/r

Substituting into the last equation yields:

P*2 = 3(24/r)

P*2 = 72/r

Multiplying both sides by 3r gives:

3Pr*2 = 216

Dividing both sides by 3P gives:

r*2 = 72/3P

r*2 = 24/P

Substituting into the second equation gives:

P*q/P = 24

q = 24

Substituting into the first equation gives:

3*r = p

In summary,

p = 6
q = 24