Question

the som of three consecutive even integers is -30

Answer 1

a = first number

b = secnod number = a + 1

c = third number = b + 1 = a + 1 + 1 = a + 2


a + b + c = 30

a + a + 1 + a + 2 = 30

3 a + 3 = 30 Subtract 3 to both sides

3 a + 3 - 3 = 30 - 3

3 a = 27 Divide both sides by 3

a = 9


first number = 9

secnod number = 9 + 1 = 10

third number = 9 + 2 = 11


Proof:

a + b + c = 30

9 + 10 + 11 = 30

30 = 30

Answer 2

I believe it was a sum of -30

no big deal ....

1st integer x-2
2nd integer x
3rd integer x+2

x-2 + x + x+2 = -30
3x = -30
x = -10

1st is -12
2nd is -10
3rd is -8