Asked by POPPY
1. Solve 5x*6×5*3*x-4
2. 3*4y*5 ×9*-2y*-2
3. 16x*5-4*-2x*3×(2x*2)*-3?
2. 3*4y*5 ×9*-2y*-2
3. 16x*5-4*-2x*3×(2x*2)*-3?
Answers
Answered by
oobleck
Not sure what your operators are. Are you using
× for multiply and
* for powers?
If so, then things are very confusing. Usually online we use
* for multiply
^ for exponents.
Maybe a few parentheses would also help...
× for multiply and
* for powers?
If so, then things are very confusing. Usually online we use
* for multiply
^ for exponents.
Maybe a few parentheses would also help...
Answered by
POPPY
x is just the normal x while the * is multiplication.
Answered by
oobleck
In that case,
5x*6×5*3*x-4
could more properly be written as
5x*6x5*3*x-4
That makes no sense either, unless you meant something like
5x * 6x^5 * 3x^-4 = (5*6*3)(x^5 * x^-4) = 90x
see what you can do with the others. That will
(a) show what you can do
(b) clarify your notation
5x*6×5*3*x-4
could more properly be written as
5x*6x5*3*x-4
That makes no sense either, unless you meant something like
5x * 6x^5 * 3x^-4 = (5*6*3)(x^5 * x^-4) = 90x
see what you can do with the others. That will
(a) show what you can do
(b) clarify your notation
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