Asked by Mike
You have been hired to help improve the material movement system at a manufacturing plant. Boxes containing 16 kg of tomato sauce in glass jars must slide from rest down a frictionless roller ramp to the loading dock, but they must not accelerate at a rate that exceeds 2.4 m/s^2 because of safety concerns.
Answers
Answered by
Mike
Part A: What is the maximum angle of inclination of the ramp?
Express your answer to two significant figures and include appropriate units.
Part B: If the vertical distance the ramp must span is 1.4 m, with what speed will the boxes exit the bottom of the ramp?
Express your answer to two significant figures and include appropriate units.
Part C: What is the normal force on a box as it moves down the ramp?
Express your answer to two significant figures and include appropriate units.
Express your answer to two significant figures and include appropriate units.
Part B: If the vertical distance the ramp must span is 1.4 m, with what speed will the boxes exit the bottom of the ramp?
Express your answer to two significant figures and include appropriate units.
Part C: What is the normal force on a box as it moves down the ramp?
Express your answer to two significant figures and include appropriate units.
Answered by
Damon
If g= 9.81/s^2
then m g sin A = 9.81 m sin A = m a = m * 2.2
or in other words sin A = 2.2 / 9.81
kinetic energy at bottom = potential at top (there is no friction)
(1/2) v^2 = g h
v = sqrt (2 * 9.81 * 1.4)
normal force = m g cos A
then m g sin A = 9.81 m sin A = m a = m * 2.2
or in other words sin A = 2.2 / 9.81
kinetic energy at bottom = potential at top (there is no friction)
(1/2) v^2 = g h
v = sqrt (2 * 9.81 * 1.4)
normal force = m g cos A
Answered by
Damon
typo, use 2.4 not 2.2
sin A = 2.4/9.81
sin A = 2.4/9.81
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