Asked by Anonymous
Solve the equation |x^2 - 2x - 6| = 4 algebraiclly, using the quadratic formula
Answers
Answered by
Reiny
|x^2 - 2x - 6| = 4
so
case 1: x^2 - 2x - 6 = 4 OR case 2: x^2 - 2x - 6 = - 4
I will do case 1, leaving it up to you to solve case 2 in the same way
x^2 - 2x - 6 = 4
x^2 - 2x - 10 = 0
x = (2 ± √44)/2
= (2 ± 2√11)/2
= 1 ± √11
so
case 1: x^2 - 2x - 6 = 4 OR case 2: x^2 - 2x - 6 = - 4
I will do case 1, leaving it up to you to solve case 2 in the same way
x^2 - 2x - 6 = 4
x^2 - 2x - 10 = 0
x = (2 ± √44)/2
= (2 ± 2√11)/2
= 1 ± √11
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