So here's the problem:

6a^-2 + 9a^2 all over 3a^-2

The answer is suppose to be 2 + 3a^4

I keep getting the answer as 5.

Can you show me how to solve this problem correctly?

1 answer

how about multiplying top and bottom of your fraction by a^2 to get

(6 + 9a^4)/3
= 2 + 3a^4