Asked by Toto

If 44.8L of carbon dioxide were produced, how many liters of oxygen must have reacted with glucose?
Answered by Damon
C6H12O6 + 3O2 ——-> 6CO2 + 6H2O

2 mols of CO2 for every mol of O2
since 22.4 liters per mol at STP for O2 and also for CO2
then 11.2 liters of O2
Answered by Damon
Whoops, sorry, not paying attention
44.8/2 = 22.4 liters CO2
There are no AI answers yet. The ability to request AI answers is coming soon!