Question
If 44.8L of carbon dioxide were produced, how many liters of oxygen must have reacted with glucose?
Answers
Damon
C6H12O6 + 3O2 ——-> 6CO2 + 6H2O
2 mols of CO2 for every mol of O2
since 22.4 liters per mol at STP for O2 and also for CO2
then 11.2 liters of O2
2 mols of CO2 for every mol of O2
since 22.4 liters per mol at STP for O2 and also for CO2
then 11.2 liters of O2
Damon
Whoops, sorry, not paying attention
44.8/2 = 22.4 liters CO2
44.8/2 = 22.4 liters CO2