Asked by sara
solve the equation below algebraically and express the result in simplest radical form
13/x=10-x
I did 13/x=10-x
multiplied each side by x and then subtracted 13 to get
0=13-(10x-x^2)
x^2-10x+13=0
x=(10+/- square root of 100-52)/2
x=(10=/- 4square root 3) /2
my answer was x=5+/- 2square root 3
was this right? thank you
13/x=10-x
I did 13/x=10-x
multiplied each side by x and then subtracted 13 to get
0=13-(10x-x^2)
x^2-10x+13=0
x=(10+/- square root of 100-52)/2
x=(10=/- 4square root 3) /2
my answer was x=5+/- 2square root 3
was this right? thank you
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