Asked by Leroy

Please help me with this Algebra problem:
The length of a rectangle is 91 less than six times the width of the rectangle. If the perimeter of the rectangle is 84 centimeters, what is the length of the rectangle? Write a system of equations for this situation and find its solution.

I have so far:

P = 2L + 2W
P = 2 (6x-91) + 2W
P = 12x -182 + 2W
2 (6x-91) =84
12x -182 =84
12x =266
Please help...I am confused...thank you
Answered by Ms. Sue
P = 2L + 2W
84 = 2 (6W-91) + 2W
84 = 14W - 182
266 = 14W
19 = Width
Answered by Reiny
Why do you have L's, W's and x's in your equation ?
width ---- w
length ---- l

equation #1:
2w + 2l = 84
w+l = 42 **

equation #2:
"The length of a rectangle is 91 less than six times the width of the rectangle"
---> l = 6w - 91
sub that back into **
w + 6w-91 = 42
7w = 133
w = 133/7 = 19
back in
l = 6w-91
= 6(19)-91 = 23
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