Asked by anonymous
A passenger is an airplane at an altitude of a=20 kilometers sees two towns directly to the east of the plane. the angles of depression to the towns are 28 degrees and 55 degrees. how far apart are the towns
Answers
Answered by
anonymous
my answer is:
sin 55 = 20/y
y=20/sin55
y=24.42
55-28=27
sin27/x=sin28/24.42
24.42sin27/sin28=23.61
is my answer correct?
sin 55 = 20/y
y=20/sin55
y=24.42
55-28=27
sin27/x=sin28/24.42
24.42sin27/sin28=23.61
is my answer correct?
Answered by
anonymous
it's okay my answers are correct
Answered by
oobleck
I don't know who confirmed your answers. Your values for y give the line-of-sight distances, not distance on the ground.
The distance is actually
20 cot28° - 20 cot55°
The distance is actually
20 cot28° - 20 cot55°
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