Question

A car moves at 12 m/s for 30.0 seconds. It then accelerates at 1.5 m/s^2 for 8.00 seconds.
Finally, it continues on at this top speed for another 12.0 seconds. Calculate the net displacement during the whole time interval.

Answers

R_scott
1st part ... d = 12 m/s * 30.0 s

2nd part ... ave speed = {12 m/s + [12 m/s + (1.5 m/s^2 * 8.00 s)]} / 2
... d = ave speed * 8.00 s

3rd part ... top speed = 12 m/s + (1.5 m/s^2 * 8.00 s)
... d = top speed * 12.0 s

add the displacements for the total
Anonymous
Doesn't elaborate or explain anything😵

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