Question
A car moves at 12 m/s for 30.0 seconds. It then accelerates at 1.5 m/s^2 for 8.00 seconds.
Finally, it continues on at this top speed for another 12.0 seconds. Calculate the net displacement during the whole time interval.
Finally, it continues on at this top speed for another 12.0 seconds. Calculate the net displacement during the whole time interval.
Answers
R_scott
1st part ... d = 12 m/s * 30.0 s
2nd part ... ave speed = {12 m/s + [12 m/s + (1.5 m/s^2 * 8.00 s)]} / 2
... d = ave speed * 8.00 s
3rd part ... top speed = 12 m/s + (1.5 m/s^2 * 8.00 s)
... d = top speed * 12.0 s
add the displacements for the total
2nd part ... ave speed = {12 m/s + [12 m/s + (1.5 m/s^2 * 8.00 s)]} / 2
... d = ave speed * 8.00 s
3rd part ... top speed = 12 m/s + (1.5 m/s^2 * 8.00 s)
... d = top speed * 12.0 s
add the displacements for the total
Anonymous
Doesn't elaborate or explain anything😵