Question

You think you can explain this to me and easiest way possible.
Fractions frighten me.
b +(7)/(8)>=(1)/(6)
I know I am suppose to get B by itself right? But when I do that do I multiple 7/8(1/6)?

Answer 1

b + 7/8 ≥ 1/6

When solving inequations, pretend you are dealing with an equation.
You can add and subtract terms on either side just like for equatios, keeping the sign the same.
You can multiply or divide each term of the inequation by the same number with
one major exception: When multiplying or dividing by a negative, you must
also reverse the inequality sign.


so let's multiply each term by +24 , the LCD for our two fractions
(24)b + (24)(7/8) ≥ (24)(1/6)
24b + 21 ≥ 4 , notice since we multiplied by a positive the sign ≥ stays the same
subtract 21 from both sides
24b + 21 - 21 ≥ 4-21 , subtraction does not affect the ≥ sign
24b ≥ -17
divide both sides by +24, so the ≥ will not be affected
24b/24 ≥ -17/24
b ≥ -17/24 <------ all done!

Our exception rule did not come into play

Answer 2

okay. I think im completely forgot about the LCD factor.. I found a inequality calculator. Insert the problem into the thingy majing and they used 2^3. Is that another shortcut or should I just work with the LCD method. It still give me the answer you stated

Answer 3

It wrote it as b+7/2^3 >= 1/6.
.....
So I have a another special case problem 40<5/8k
Do I just write it as 40/1<5/8 or do I still need the common denominator

Answer 4

b + 7/8 >= 1/6.
b >= 1/6 - 7/8,
b >= 4/24 - 21/24,
b >= -17/24.

Do you mean 40 < (5/8)k ? If so:
40 < 5k/8.
Multiply both sides by 8:
320 < 5k,
320/5 < 5k/5,
64 < k.