Asked by A
For what value of k does the equation x2 + kx + 9have:
Two distinct real roots
One real root
No real root
Two distinct real roots
One real root
No real root
Answers
Answered by
Spring Allergies
One real root.
Answered by
Reiny
First of all you don't have an equation, you must have meant:
x^2 + kx + 9 = 0
For two distinct real roots, the discriminant b^2 - 4ac > 0
k^2 - 4(1)(9) > 0
k^2 > 36
±k > 6
k > 6 or k < -6
To have 1 root, the discriminant b^2 - 4ac must be zero
k^2 - 4(1)(9) = 0
k^2 = 36
k = ± 6
So what do you think must be the value of b^2 - 4ac to have no real roots ?
x^2 + kx + 9 = 0
For two distinct real roots, the discriminant b^2 - 4ac > 0
k^2 - 4(1)(9) > 0
k^2 > 36
±k > 6
k > 6 or k < -6
To have 1 root, the discriminant b^2 - 4ac must be zero
k^2 - 4(1)(9) = 0
k^2 = 36
k = ± 6
So what do you think must be the value of b^2 - 4ac to have no real roots ?
Answered by
A
6 > k > -6 no roots?
Answered by
Reiny
yes, I would prefer you last statement to say
-6 < k < 6
I know it is the same thing as your answer, but traditionally let's go
from left to right . Visualize the number line, negatives on the left.
for -10 < x < 10 , I visualize x to be between -10 and + 10
-6 < k < 6
I know it is the same thing as your answer, but traditionally let's go
from left to right . Visualize the number line, negatives on the left.
for -10 < x < 10 , I visualize x to be between -10 and + 10
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