eric has a pair of identical number cubes.the face of each of each cube are numbered 1-6.eric will roll the cubes both at the same time.what is the probability that the numbers showing face-up after the roll will be multiples of 3?
A)2/9
B)1/3
C)1/6
D)1/9
6 answers
Give me assistance por favore, i think it's B
Do the math here. The numbers on a die are 1 to 6 (1,2,3,4,5,6) and there are two multiples of 3 in 1 -6, 3 and 6. so that's 2 numbers out of 6, 2/6, simplified would be?
1/3, so B was right?
There are only 2 faces on each die that are multiples of 3: 3,6
So, the chance that a die will show 3 or 6 is 2/6 = 1/3
The chance that both dice will show one of those faces is
1/3 * 1/3 = 1/9
So, the chance that a die will show 3 or 6 is 2/6 = 1/3
The chance that both dice will show one of those faces is
1/3 * 1/3 = 1/9
Yep, that's right!
tysm
15 answers