Question
P4O10(s) + 6 H2SO4(l) --> 4 H3PO4(aq) + 6 SO3(g)
Pure H2SO4(l) has a density of 1.84 g/mL. If 45.0 mL of H2SO4(l) reacts:
What mass of P4O10 reacts?
- it's given 45.0 mL of H2SO4 with the density of 1.84 g/mL, so the mass of H2SO4 is 45*1.84 = 82.8 (g) so converts to 0.845 moles of H2SO4
- the ratio between P4O10 and H2SO4 is 1 : 6, so the moles of P4O10 reacting is 0.141
so the mass of P4O10 reacts is 0.141*284 = 40.044 (g)
What volume of SO3(g) at STP is produced?
- the ratio between H2SO4 and SO3 is 1 : 1, so the moles of SO3 produced is 0.845
so the volume of P4O10 produced is 0.845*22.4 = 18.928 (L) in STP
A 200. mL sample of H3PO4 is titrated with 56.2 mL of 0.700M NaOH.
2 NaOH(s) + H3PO4(l) --> Na2HPO4(s) + 2H2O(l)
a) What is the molar concentration of H3PO4?
it's given 56.2 mL of 0.700M NaOH, so converts to 56.2/1000*0.7 = 0.04 moles of NaOH
- the ratio between NaOH and H3PO4 is 2 : 1, so the moles of H3PO4 needed is 0.02
- 0.02 moles H3PO4 in a 200 mL sample of H3PO4, that means the molar concentration of H3PO4 is 0.02/(200/1000) = 0.1(moles/L)
b) How many moles of Na2HPO4 are produced? (2 marks)
- the ratio between NaOH and Na2HPO4 is 2 : 1, so the moles of Na2HPO4 produced is 0.02
Pure H2SO4(l) has a density of 1.84 g/mL. If 45.0 mL of H2SO4(l) reacts:
What mass of P4O10 reacts?
- it's given 45.0 mL of H2SO4 with the density of 1.84 g/mL, so the mass of H2SO4 is 45*1.84 = 82.8 (g) so converts to 0.845 moles of H2SO4
- the ratio between P4O10 and H2SO4 is 1 : 6, so the moles of P4O10 reacting is 0.141
so the mass of P4O10 reacts is 0.141*284 = 40.044 (g)
What volume of SO3(g) at STP is produced?
- the ratio between H2SO4 and SO3 is 1 : 1, so the moles of SO3 produced is 0.845
so the volume of P4O10 produced is 0.845*22.4 = 18.928 (L) in STP
A 200. mL sample of H3PO4 is titrated with 56.2 mL of 0.700M NaOH.
2 NaOH(s) + H3PO4(l) --> Na2HPO4(s) + 2H2O(l)
a) What is the molar concentration of H3PO4?
it's given 56.2 mL of 0.700M NaOH, so converts to 56.2/1000*0.7 = 0.04 moles of NaOH
- the ratio between NaOH and H3PO4 is 2 : 1, so the moles of H3PO4 needed is 0.02
- 0.02 moles H3PO4 in a 200 mL sample of H3PO4, that means the molar concentration of H3PO4 is 0.02/(200/1000) = 0.1(moles/L)
b) How many moles of Na2HPO4 are produced? (2 marks)
- the ratio between NaOH and Na2HPO4 is 2 : 1, so the moles of Na2HPO4 produced is 0.02
Answers
Looks good to me, except for 2B. Double check that one. The moles of H3PO4 are proportional to its conjugate base.
Nevermind. That one is correct as well.
Thank you !
H3PO4/H2SO4 problem is OK>
For M H3PO4 I get 0.098M
For mols Na2HPO4 I get 0.0196
For M H3PO4 I get 0.098M
For mols Na2HPO4 I get 0.0196
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