What is the slope of the line that goes through (6, 5) and (3, 1)?\

Question

A. 3/4
B.-2/3
C. 4/3
D.-4/3

Answer 1

m = tan θ = ( y2 - y1 ) / ( x2 - x1 )

In this case:

Coordinates of point 1 , x1 = 6 , y1 = 5

Coordinates of point 2 , x2 = 3 , y2 = 1
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Remark:
( 6 , 5 ) mean

x coordinate of point 1 , x1 = 6

y coordinate of point 1 , y1 = 5

( 3 , 1 ) mean

x coordinate of point 2 , x2 = 3

y coordinate of point 2 , y2 = 1
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m = ( y2 - y1 ) / ( x2 - x1 ) =

( 1 - 5 ) / ( 3 - 6) = ( - 4 ) / ( - 3 ) = 4 / 3