Question
What is the slope of the line
10x-2=7
a
-2
b
-10
c
10
10x-2=7
a
-2
b
-10
c
10
Answers
GPT-4o mini
To find the slope of the line represented by the equation \(10x - 2 = 7\), we first need to rearrange the equation into the slope-intercept form \(y = mx + b\), where \(m\) is the slope.
Starting with the equation:
\[
10x - 2 = 7
\]
First, we can isolate \(10x\) by adding 2 to both sides:
\[
10x = 9
\]
Next, to express this in slope-intercept form, we can solve for \(y\). However, this equation does not have a \(y\) term. Instead, we can express this equation as \(y = 0\) or think of it as a vertical line corresponding to the x-value of \(x = \frac{9}{10}\).
Alternatively, since the equation does not represent \(y\) in terms of \(x\), it does not fit within the standard approach to determining slope in lines. The slope is undefined because it is not expressed as a function of \(y\) that changes with \(x\).
But if we insisted on the original equation being a function of \(y\) with any \(y\) constants added, it would just imply a horizontal line where \(y=0\), which interpretively can be loosely connected to being a slope of 0.
None of the options given (-2, -10, or 10) measure up correctly against this re-evaluation either.
Thus, we can conclude,
none of the options correctly represent a slope interpretation from that equation, which is more positional than linear with coordinates defined as is.
Starting with the equation:
\[
10x - 2 = 7
\]
First, we can isolate \(10x\) by adding 2 to both sides:
\[
10x = 9
\]
Next, to express this in slope-intercept form, we can solve for \(y\). However, this equation does not have a \(y\) term. Instead, we can express this equation as \(y = 0\) or think of it as a vertical line corresponding to the x-value of \(x = \frac{9}{10}\).
Alternatively, since the equation does not represent \(y\) in terms of \(x\), it does not fit within the standard approach to determining slope in lines. The slope is undefined because it is not expressed as a function of \(y\) that changes with \(x\).
But if we insisted on the original equation being a function of \(y\) with any \(y\) constants added, it would just imply a horizontal line where \(y=0\), which interpretively can be loosely connected to being a slope of 0.
None of the options given (-2, -10, or 10) measure up correctly against this re-evaluation either.
Thus, we can conclude,
none of the options correctly represent a slope interpretation from that equation, which is more positional than linear with coordinates defined as is.