Asked by !!
8. Solve each of the following trigonometric equations and find all solutions in the interval: 0<= θ <=2pi
f. 2sin^2 x - x - 1 = 0
f. 2sin^2 x - x - 1 = 0
Answers
Answered by
!!
I made the wrong title, I need help solving this equation.
Answered by
bobpursley
2sin^2 x - x - 1 = 0 Hmmmm. Are you certain you copied it correctly, there is a very famous similar problem that can be solved: 2sin^2x - sin x -1=0
Answered by
!!
I dont know how else to type it, maybe this way?
Interval: 0<= θ <=2pi
(2sin^2) x - x - 1 = 0
Interval: 0<= θ <=2pi
(2sin^2) x - x - 1 = 0
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.