Asked by !!

8. Solve each of the following trigonometric equations and find all solutions in the interval: 0<= θ <=2pi

f. 2sin^2 x - x - 1 = 0

Answers

Answered by !!
I made the wrong title, I need help solving this equation.
Answered by bobpursley
2sin^2 x - x - 1 = 0 Hmmmm. Are you certain you copied it correctly, there is a very famous similar problem that can be solved: 2sin^2x - sin x -1=0
Answered by !!
I dont know how else to type it, maybe this way?

Interval: 0<= θ <=2pi

(2sin^2) x - x - 1 = 0
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