Asked by A.normal.tree
Please help I'm very confused
Find the lateral area of a square pyramid. Base: 8, Height: 22, and side: 8
Find the lateral area of a square pyramid. Base: 8, Height: 22, and side: 8
Answers
Answered by
A.normal.tree
Please
Answered by
oobleck
I'm confused too: Base: 8, Height: 22, and side: 8 ?
Do you mean a square base with side 8?
If so, draw a side view. The altitude from the vertex to the base lands in the center of the square, 4 units from each side. Then the slant height can be found using
s^2 = 4^2+22^2
s = 10√5
The lateral area is just the areas of the four slanting triangular sides, each with base 8 and height s. So,
area = 4 * (8*10√5)/2 = 160√5
Do you mean a square base with side 8?
If so, draw a side view. The altitude from the vertex to the base lands in the center of the square, 4 units from each side. Then the slant height can be found using
s^2 = 4^2+22^2
s = 10√5
The lateral area is just the areas of the four slanting triangular sides, each with base 8 and height s. So,
area = 4 * (8*10√5)/2 = 160√5
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