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Asked by isaac-

in a nonagon 6 of the angles are equal,and
each of the other three is 33 more than each of the 6 angles..find the angles
6 years ago

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Answered by ghost
whats your answers
6 years ago
Answered by oobleck
this has already been answered for you, but why not again?
6x + 3(x+33) = (9-2)*180
6 years ago
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in a nonagon 6 of the angles are equal,and
each of the other three is 33 more than each of the 6 angles..find the angles

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