Asked by IFE
In a nonagon, six of the angles are equal, and each of the other three angles is 33degree more than each of the six angles.Find the angles.
Answers
Answered by
scott
the sum of the internal angles of a nonagon is ... (9 * 180º) - 360º
6 a + [3 * (a + 33)] = (9 * 180º) - 360º
6 a + [3 * (a + 33)] = (9 * 180º) - 360º
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