Question

A velocity selector is built with a magnetic field of magnitude 5.2 T and an electric field of strength 4.6 × 10 ^4 N/C. The directions of the two fields are perpendicular to each other. At what speed will electrons pass through the selector without deflection? Let the charge of an electron q = −1.6 × 10 ^ −19
A.8.8 × 10^3 m/s
B 2.4 × 10 ^ - 15 m/s
C 7.9 × 10 ^ 13 m/s
D 2.0 x 10 ^ 4 m/s

Answer 1

set the two forces equal.
Eq =q vB

v= E/B=4.6e4/(5.2)= ..... m/second

Answer 2

q E = q V B
V = E/B for any old q
= 4.6*10^4 / 5.2

Answer 3

that's not an answer choice.

Answer 4

what was the answer

Answer 5

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