Asked by lol

A car traveling at 25 mi/h accelerates to 48 mi/h over the first 5 seconds. It maintains that speed for the next 5 seconds, and then slows to a stop during the next 5 seconds. does anyone know because i have no clue here?
Answered by bobpursley
wondering what the question is? If the question is how far does the car travel, the answer is easy:
Plot a graph of speed (in meters/second) vs time. You will have to convert all those silly mph speeds to m/s. Then, the area below the graph is distance (speed *time= distance). Break it up into simple geometric shapes, then get area. Area= distance.
Answered by Henry2,
Vo = 25mi/h * 1600m/mi * 1h/3600s = 11.11 m/s.
V = 48/25 * 11.11 = 21.33 m/s.

V = Vo + a*t = 21.33.
11.11 + a*5 = 21.33,
a = 2.04 m/s^2.
V^2 = Vo^2 + 2a*d1 = (21.33)^2.
(11.11)^2 + 4.08*d1 = 455,
d1 = 81.3 m.

d2 = V*t = 21.33 * 5 = 106.7 m.

V = Vo + a*t = 0.
21.33 + a*5 = 0,
a = - 4.27 m/s^2.
V^2 = Vo^2 + 2a*d3 = 0.
(21.33)^2 + (-8.54)d3 = 0,
d3 = 53.3 m. = Stopping distance.

D = d1 + d2 + d3 = 81.3 + 106.7 + 53.3 = 241.3 m. = Total distance traveled.


Answered by Steve still stink after decades.
disgusting nasty smelling Steve
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