Asked by Anonymous
Selena took 20 seconds to swim from point A to point B at a speed of 4.5 m/s. She took 18 seconds to swim back from point A to point B.
Find Selena's average speed when she swam from Point B to Point A
(Help me get to the answer please ty)
Find Selena's average speed when she swam from Point B to Point A
(Help me get to the answer please ty)
Answers
Answered by
Bosnian
Velocity:
v = s / t
where
v = velocity or speed ( m / sec )
s = linear distance traveled ( m)
t = time ( sec )
Selena took 20 seconds to swim from point A to point B at a speed of 4.5 m /s mean:
v = 4.5 m / sec
t = 20 sec
v = s / t
4.5 = s / 20
s = 4.5 ∙ 20 = 90 m
This mean linear distance point A to point B = 90 m
Linear distance point B to point A is also = 90 m
So for point B to point A:
v = s / t
v = 90 / 18 = 5 m / s
v = s / t
where
v = velocity or speed ( m / sec )
s = linear distance traveled ( m)
t = time ( sec )
Selena took 20 seconds to swim from point A to point B at a speed of 4.5 m /s mean:
v = 4.5 m / sec
t = 20 sec
v = s / t
4.5 = s / 20
s = 4.5 ∙ 20 = 90 m
This mean linear distance point A to point B = 90 m
Linear distance point B to point A is also = 90 m
So for point B to point A:
v = s / t
v = 90 / 18 = 5 m / s
Answered by
Anonymous
Thanks!
Answered by
I am the ONE The oNE
Bosnian i think you are the new Albert Einstein
Answered by
Henry2,
d = V * t = 4.5m/s * 20s = 90 m.
d = V * t = 90.
V * 18 = 90,
V = 5 m/s.
d = V * t = 90.
V * 18 = 90,
V = 5 m/s.
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