Asked by john

Jane is organizing a fundraiser to buy a ping-pong table for the community center. The table costs $500.00. Jane is asking contributors to pay for an equal share of the cost of the table. She already has five contributors lined up. What function models the cost per share, C, with respect to the number of new contributors, n? How many new contributors must Jane recruit in order for the cost of each share to be $20.00?

Answers

Answered by john
I've gotten 20 and 25 as an answer im so confused.
Answered by Ms. Sue
500 / 20 = 25 contributors
Answered by Damon
but that is 20 ADDITIONAL contributers
500 = 20 (n+5)
20 n + 100 = 500
20 n = 400
n = 20
Answered by Ms. Sue
Oops! I didn't read carefully. Thanks, Damon.
Answered by john
thanks guys
Answered by Jacob
ESKETIT
Answered by Ajax
Someone buy me welkin moon for genshin
Answered by Dafuq
CAN I GET AN OHHH YEAHH!!!!
Answered by ;)
OHHHHH YEAH
Answered by William
Hey Damon I just had a quick question.In the function that we use to model the cost per share,c, with respect to the number of new contributors,n, do we have to include the variable c like you did with the variable n?
Answered by Spock
Hey, William! I don't know if you still need to know this, but the regular function would be 500 = C (n + 5) if you were to include the C.
Answered by Anonymous
guys this school sucks 😭😭
Answered by muah
man im gonna fail LOL
Answered by kyungsoo
i hate it here
Answered by Ipop
same its not even a real school.
Answered by Some Fangirl
Thanks guys I really needed help on this problem you’re the best.
Answer is still right in 2022
Answered by f2p genshin boy
lmao whoever asked for welkin moon same
Answered by Random
The fact that I look up the answer then after I get it I just read what y’all weirdos comment just to laugh 🤦🏽‍♂️
Answered by Human
Ya'll are wrong.
5 contributors offered to pay for 2 shares.
The equation 500= C(n+5) is if each contributor payed for one share
If each contributor is paying 2 shares each that is 10 shares in total.
500= C(n+10)
500=20(n+10)
500=20n+200
-200 each side
300=20n
Divide both sides by 20
15=n
15 new contributors
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