Question
In a cathode-ray tube, electrons are projected horizontally at 6.4 x 106 m/s and travel a horizontal distance of 4.7 cm across the tube. Find the vertical distance the electrons fall under the influence of gravity during their flight. Give your answer in femtometers.
Answers
bobpursley
time to fall= 4.6e-2/6.4e6 sec=7.2e-9 sec
fall distance= .5*9.8*(7.2e-9)^2=2.5e-16m= .25fm
fall distance= .5*9.8*(7.2e-9)^2=2.5e-16m= .25fm