Asked by julia

In a cathode-ray tube, electrons are projected horizontally at 1.0×10^6 m/s and travel a horizontal distance 11.5 cm across the tube.
How long are the electrons in flight?
Express your answer to two significant figures and include the appropriate units.
Find the vertical distance the electrons fall (under the influence of gravity) during their flight.
Express your answer to two significant figures and include the appropriate units.

Answers

Answered by Damon
t = distance/speed = .115 * 10^-6 seconds
which is
1.2 *10^-7 seconds


h = (1/2) g t^2
h = 4.9 (1.44)(10^-14)
h = 7.1 * 10^-14 meters


Answered by julia
supposedly the answer to the second part of the question is y = −6.5×10−14 m
any insight?
Answered by Damon
I rounded .115 to .12 in part a
(as instructed :)

If they use 4.9 (1.15)^2
they would get 6.48
which rounds to 6.5

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