Asked by sarah
Find the longest side of triangle ABC, if measurement A=70, measurement B=2x-10, and measurement C=3x+20.
Answers
Answered by
Chopsticks
5x-10=80 x=16
B=2(16) - 10 = 22
C= 3(16)+20 = 68
I'm not sure if that's right or not.
B=2(16) - 10 = 22
C= 3(16)+20 = 68
I'm not sure if that's right or not.
Answered by
Reiny
I will assume that by "measurement A=70" you are referring to angle A
then 70 + 2x-10 + 3x+20 = 180
5x = 100
x = 20
then angle B = 30 and
angle C = 80
knowing that in any triangle, the largest side is opposite the largest angle, the largest side must be opposite angle C, which would be AB
then 70 + 2x-10 + 3x+20 = 180
5x = 100
x = 20
then angle B = 30 and
angle C = 80
knowing that in any triangle, the largest side is opposite the largest angle, the largest side must be opposite angle C, which would be AB
Answered by
DM
Find the pattern
Give the formula
0 -- 8
1 -- 11
2 -- 14
3 -- 17
4 --
5 --
50 --
n --
Give the formula
0 -- 8
1 -- 11
2 -- 14
3 -- 17
4 --
5 --
50 --
n --
Answered by
uh
y'all homies wrong
Answered by
ethan
reiny is correct