Asked by utulu Daniel
a tractor of mass 5.0×10^3kg is used to tow a car of mass 2.5×10^3kg. The tractor moved with a speed of 3.0m/s just before the towing rope became taut.
1. Find the speed of the tractor immediately the rope becomes taut
2. loss in kinetic energy of the system just after the car has started moving
3. impulse in the rope when it jerks the car into motion
1. Find the speed of the tractor immediately the rope becomes taut
2. loss in kinetic energy of the system just after the car has started moving
3. impulse in the rope when it jerks the car into motion
Answers
Answered by
Henry2,
Given:
M1 = 5000kg, Vi = 3m/s.
M2 = 2500kg, V2 = 0 before taut.
V3 = Velocity of M1 after taut(tight).
Momentum before taut = Momentum after taut.
M1*V1 = (M1+M2)V3.
5000 * 3 = 7500*V3,
V3 = 2 m/s.
Note: The car is not a part of the system until the rope becomes taut(tight).
M1 = 5000kg, Vi = 3m/s.
M2 = 2500kg, V2 = 0 before taut.
V3 = Velocity of M1 after taut(tight).
Momentum before taut = Momentum after taut.
M1*V1 = (M1+M2)V3.
5000 * 3 = 7500*V3,
V3 = 2 m/s.
Note: The car is not a part of the system until the rope becomes taut(tight).
Answered by
Denny krugher
Define the word; IMPULSE
Answered by
Benji
The like are not complete and the solution is in short ways
Answered by
Ahmad
I need an answer
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.