Asked by utulu Daniel

a tractor of mass 5.0×10^3kg is used to tow a car of mass 2.5×10^3kg. The tractor moved with a speed of 3.0m/s just before the towing rope became taut.
1. Find the speed of the tractor immediately the rope becomes taut
2. loss in kinetic energy of the system just after the car has started moving
3. impulse in the rope when it jerks the car into motion
Answered by Henry2,
Given:
M1 = 5000kg, Vi = 3m/s.
M2 = 2500kg, V2 = 0 before taut.
V3 = Velocity of M1 after taut(tight).

Momentum before taut = Momentum after taut.
M1*V1 = (M1+M2)V3.
5000 * 3 = 7500*V3,
V3 = 2 m/s.

Note: The car is not a part of the system until the rope becomes taut(tight).
Answered by Denny krugher
Define the word; IMPULSE
Answered by Benji
The like are not complete and the solution is in short ways
Answered by Ahmad
I need an answer
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