Question

A 5.00 g sample of aluminum pellets (specific heat capacity = 0.89 J/°C·g) and a 10.00 g sample of iron pellets (specific heat capacity = 0.45 J/°C·g) are heated to 100.0°C. The mixture of hot iron and aluminum is then dropped into 94.9 g of water at 24.2°C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings.

Answer 1

sum of heats gained is zero.
5*.89(Tf-100)+10*.45(Tf-100)+94.0(4.18)(Tf-24.2)=0
solve for Tf

Answer 2

Okay got it thank you!