Asked by mamush
what is the pressure at apoint 10 m below the free surface in fluid that has with solution variable density in kg/m3 given by p=45+ah, in which a=12 kg/m4 and h is the distance measured from the free surface with solution
Answers
Answered by
Motorhead
From your given equation (using p as rho), the density at that depth is:
p = 45 kg/m³ + (12 kg/m^4)(10 m)
p = 165 kg/m³
Pressure = pgh
= (165 kg/m³)(9.8 m/s ² )(10 m)
= 16170 kg/m-s²
= 16170 Pa
= 16.17 kPa
p = 45 kg/m³ + (12 kg/m^4)(10 m)
p = 165 kg/m³
Pressure = pgh
= (165 kg/m³)(9.8 m/s ² )(10 m)
= 16170 kg/m-s²
= 16170 Pa
= 16.17 kPa
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.