Asked by heather
At a pressure 43 kPa, the gas in a cylinder has a volume of 11 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 5 liters, what is the new pressure?
kPa
Im guessing it 58 or 77x10^3
kPa
Im guessing it 58 or 77x10^3
Answers
Answered by
Steve
PV=kT
so, since T is constant, so is PV. You want P such that
P*5 = 43*11
P = 94.6
so, since T is constant, so is PV. You want P such that
P*5 = 43*11
P = 94.6
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.