Asked by David
How many moles of sulfur dioxide are produced when 72.0 grams of water is produced by the process:
2H2S + 3O2 ---> 2H2O +2SO2
2H2S + 3O2 ---> 2H2O +2SO2
Answers
Answered by
Anonymous
72.0g of H2O is roughly 4 moles of H2O. So, 4 moles of SO2 are produced, according to the balanced reaction.
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