Asked by Anonymous
A bag contains five red marbles and five blue marbles. You randomly pick a marble and then return it to the bag before picking another marble. The first marble is red and the second marble is blue.
a. 1/4 = 0.25 *****
b. 21/55 = 0.382
c. 1/17 = 0.059
d. 14/55 = 0.255
a. 1/4 = 0.25 *****
b. 21/55 = 0.382
c. 1/17 = 0.059
d. 14/55 = 0.255
Answers
Answered by
Sarah
What is the question?
Answered by
Anonymous
That was the whole problem It does not make sense to me because it does not ask a question.
Answered by
Sarah
Maybe the question is: What is the probability of getting a red marble first and then a blue marble second?
Answered by
Sarah
There are a total of 10 marbles.
The probability of getting a red marble 5/10 = 1/2.
Then you put that red marble back, so the total is 10 marbles again.
The second try, the probability of getting a blue marble 5/10 = 1/2.
When you want to know what the probability of two events happening one after the other, you multiply each events probability.
The probability of getting a red marble AND THEN a blue marble: 1/2 * 1/2 = 1/4
The probability of getting a red marble 5/10 = 1/2.
Then you put that red marble back, so the total is 10 marbles again.
The second try, the probability of getting a blue marble 5/10 = 1/2.
When you want to know what the probability of two events happening one after the other, you multiply each events probability.
The probability of getting a red marble AND THEN a blue marble: 1/2 * 1/2 = 1/4
Answered by
Anonymous
Thank you
Answered by
Sarah
You're welcome!
Answered by
mohammad
A bag contains six red marbles and three blue marbles. Another bag contains seven green marbles and six yellow marbles. You randomly pick one marble from each bag. What is the probability that one marble is blue and one marble is yellow?